NCERT Class XI Chemistry Structure of Atom Solutions
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Question : 34
Total: 67
Calculate the energy required for the process, H e ( g ) + → H e 2 + ( g ) + e – .
The ionization energy for the H atom in the ground state is 2.18 ×10 – 18 J atom – 1 .
The ionization energy for the H atom in the ground state is 2.18 ×
Solution:
Energy required = E ∞ – E 1 = − ( −
× Z 2 ) =
= 8.72 ×10 − 18 J
= 8.72 ×
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