NCERT Class XI Chemistry Structure of Atom Solutions

Question : 59

Total: 67

If the velocity of the electron in Bohr’s first orbit is 2.19 × 106ms–1, calculate the de Broglie wavelength associated with it.

Solution:

We know that, λ =

where, h = 6.626 × 10–34 J s,
m = mass of electron = 9.1 × 10–31kg, v = 2.19 × 106m∕s
∴ λ =

6.626×10−34

9.1×10−31×2.19×106

= 0.32 × 10−9m = 332 × 10−12m
λ = 332 pm [Since 1 pm = 10−12m]

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