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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 60
Total: 67
The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 105ms–1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.
Solution:  
We know that λ =
h
mv
where h = 6.626 × 10–34Js, m = 0.1 kg, v = 4.37 × 105ms–1
∴ λ =
6.626×10−34
0.1×4.37×105
 = 15.16 × 10−39m = 1.516 × 10−38m
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