NCERT Class XI Chemistry The p-Block Elements Solutions

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Question : 20
Total: 38
What happens when :
(a) Borax is heated strongly.
(b) Boric acid is added to water.
(c) Aluminium is treated with dilute NaOH.
(d) BF3 is reacted with ammonia.
Solution:  
(a) When powdered borax is heated strongly on the bunsen burner, it forms colourless transparent glassy (glass like) bead made of sodium metaborate and boric anhydride.
Na2B4O7.10H2O
Heat
Na2B4O7
Heat
2NaBO2+B2O3
Transparentglassybead

(b) It dissolves in water behaving as Lewis acid. It forms [B(OH)4] by accepting a pair of electrons from OH–.
B(OH)3+HOH[B(OH)4]+H+.
(c) Aluminium dissolves in NaOH solution to form a soluble complex and liberates hydrogen gas.
2Al(s)+2NaOH(aq)+6H2O(l)
2Na[Al(OH)4](aq)
Solublecomplex
+3H2(g)

(d) BF3 (Lewis acid in nature) forms an addition compound with NH3 (Lewis base in nature).
F
F
|
B
|
F
Lewisbase(Acceptor)
+
:
H
|
N
|
H
H
Lewisbase(Donor)
[F
F
|
B
|
F
:
H
|
N
|
H
H
]
Additioncompound

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