NCERT Class XI Chemistry The p-Block Elements Solutions

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Question : 21
Total: 38
Explain the following reactions :
(a) Silicon is heated with methyl chloride at high temperature in the presence of copper;
(b) Silicon dioxide is treated with hydrogen fluoride;
(c) CO is heated with ZnO;
(d) Hydrated alumina is treated with aqueous NaOH solution.
Solution:  
(a) When methyl chloride reacts with silicon in the presence of copper as a catalyst at a temperature 573 K various types of methyl substituted chlorosilane of formula MeSiCl3,Me2SiCl2,Me3SiCl with small amount of Me4Si are formed.
2CH3Cl+Si
Cu‌powder
→
573K
(CH3)SiCl3+(CH3)2SiCl2 + (CH3)3SiCl+(CH3)4Si
(b) When silicon dioxide is treated with HF, silicon tetrafluoride is formed.
SiO2+4HF → SiF4+2H2O
(c) CO is a powerful reducing agent, it reduces ZnO to Zn.
CO(g)+ZnO(s)
Δ
→
Zn(s)+CO2(g) ↑
(d) Aluminium reacts with aqueous alkali and liberates hydrogen gas.
2Al(s)+2NaOH(aq)+6H2O(l) → 2Na+[Al(OH)4](aq)−+3H2(g) ↑
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