NCERT Class XI Chemistry Thermodynamics Solutions
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Question : 20
Total: 22
The equilibrium constant for a reaction is 10. What will be the value of ΔG° ?
R = 8.314J K – 1 m o l – 1 , T = 300 K.
R = 8.314
Solution:
We know that ΔG° = –2.303RT logK = –2.303 × 8.314 × 300 × log10
= –5744.14 J/mol
= –5744.14 J/mol
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