NCERT Class XI Chemistry Thermodynamics Solutions

© examsnet.com
Question : 20
Total: 22
The equilibrium constant for a reaction is 10. What will be the value of ΔG° ?
R = 8.314 JK1mol1, T = 300 K.
Solution:  
We know that ΔG° = –2.303RT logK = –2.303 × 8.314 × 300 × log10
= –5744.14 J/mol
© examsnet.com
Go to Question: