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NCERT Class XI Chemistry Thermodynamics Solutions

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Question : 21
Total: 22
Comment on the thermodynamic stability of NO(g), given
1
2
N2(g)+
1
2
O2(g) → NO(g) ; ΔrH° = 90 kJmol−1
NO(g)+
1
2
O2(g) → NO2(g) ; ΔrH° = - 74 kJmol−1
Solution:  
Since ΔrH° is +ve, i.e., enthalpy of formation of NO is positive, therefore NO is unstable. But ΔrH° is negative for the formation of NO2. So, NO2 is stable.
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