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NCERT Class XI Chemistry Thermodynamics Solutions

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Question : 4
Total: 22
ΔU° of combustion of methane is – X kJmol–1. The value of ΔH° is
Solution:  
CH4(g)+2O2(g) → CO2(g)+2H2O(l)
Δn = 1 - 3 = - 2.
ΔH° = ΔU° + ΔnRT = - X - 2RT
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