NCERT Class XI Mathematics - Binomial Theorem - Solutions

© examsnet.com
Question : 2
Total: 36
(
2
x
x
2
)
5
Solution:  
We have, (
2
x
x
2
)
5
= [
2
x
+(
x
2
)
]
5

=
5
C0[
2
x
]
5
+
5
C1[
2
x
]
4
[
x
2
]
+
5
C2[
2
x
]
3
[
x
2
]
2
+
5
C3[
2
x
]
2
[
x
2
]
3
+
5
C4[
2
x
]
[
x
2
]
4
+
5
C5[
x
2
]
5

= 1 [
32
x5
]
+5(
8
x3
)
(1)
+ 10 [
2
x
]
+ 10 [
x
2
]
+5[
x3
8
]
+[
x5
32
]

=
31
x5
40
x3
+
20
x
- 5x +
5x3
8
x5
32
© examsnet.com
Go to Question: