NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 3
Total: 36
(2x−3)6
Solution:  
We have, (2x−3)6 = [2x+(−3)]6
=
6
‌
C0(2x)6
+
6
‌
C1(2x)5(−3)
+
6
‌
C2(2x)4(−3)2
+
6
‌
C3(2x)3(−3)2
+
6
‌
C4(2x)2(−3)4
+
6
‌
C5(2x)(−3)5
+
6
‌
C6(−3)6

= 1(64x6)+6(32x5)(−3) + 15(16x4)(9)+20(8x3)(−27) + 15(4x2)(81) + 6(2x)(−243)+1(729)
= 64x6−576x5+2160x4−4320x3 + 4860x3+4860x2 - 2916x + 729
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