NCERT Class XI Mathematics - Conic Sections - Solutions
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Question : 2
Total: 71
centre (–2, 3) and radius 4
Solution:
Here h = –2, k = 3 and r = 4
The equation of circle is,( x – h ) 2 + ( y – k ) 2 = r 2
∴( x + 2 ) 2 + ( y – 3 ) 2 = ( 4 ) 2 ⇒ x 2 + 4 + 4x + y 2 + 9 – 6y = 16
⇒x 2 + y 2 + 4x – 6y – 3 = 0
The equation of circle is,
∴
⇒
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