NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 3
Total: 71
centre (
1
2
,
1
4
)
and radius
1
12
Solution:  
Here h =
1
2
, k =
1
4
and r =
1
12

The equation of circle is, (xh)2+(yk)2 = r2
(x+
1
2
)
2
+(y
1
4
)
2
= (
1
12
)
2
x2+
1
4
x
+y2
+
1
16
1
2
y
=
1
144

144x2 + 36 – 144x + 144y2 + 9 – 72y = 1
144x2+144y2 – 144x – 72y + 44 = 0
⇒ 4(36x2+36y2 – 36x – 18y + 11) = 0
36x2+36y2 – 36x – 18y + 11 = 0
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