NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 3
Total: 71
centre (
1
2
,
1
4
)
and radius
1
12
Solution:  
Here h =
1
2
, k =
1
4
and r =
1
12

The equation of circle is, (x–h)2+(y–k)2 = r2
∴ (x+
1
2
)
2
+(y−
1
4
)
2
= (
1
12
)
2
⇒ x2+
1
4
−x
+y2
+
1
16
−
1
2
y
=
1
144

⇒ 144x2 + 36 – 144x + 144y2 + 9 – 72y = 1
⇒ 144x2+144y2 – 144x – 72y + 44 = 0
⇒ 4(36x2+36y2 – 36x – 18y + 11) = 0
⇒ 36x2+36y2 – 36x – 18y + 11 = 0
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