NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 5
Total: 71
centre (–a, –b) and radius a2b2
Solution:  
Here h = –a, k = –b and r = a2b2
The equation of circle is, (xh)2+(yk)2 = r2
(x+a)2+(y+b)2 = (a2b2)2
x2+a2 + 2ax + y2+b2 + 2by = a2b2x2+y2 + 2ax + 2by + 2b2 = 0
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