NCERT Class XI Mathematics - Conic Sections - Solutions
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Question : 5
Total: 71
centre (–a, –b) and radius √ a 2 − b 2
Solution:
Here h = –a, k = –b and r = √ a 2 − b 2
The equation of circle is,( x – h ) 2 + ( y – k ) 2 = r 2
∴( x + a ) 2 + ( y + b ) 2 = ( √ a 2 − b 2 ) 2
⇒x 2 + a 2 + 2ax + y 2 + b 2 + 2by = a 2 – b 2 ⇒ x 2 + y 2 + 2ax + 2by + 2 b 2 = 0
The equation of circle is,
∴
⇒
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