The given equation of circle is, (x+5)2+(y–3)2 = 36
⇒ (x+5)2+(y–3)2 = (6)2
Comparing it with (x–h)2+(y–k)2 = r2, we get h = –5, k = 3 and r = 6.
Thus the co-ordinates of the centre are (–5, 3) and radius is 6.