The given equation of circle is, 2x2+2y2 – x = 0
∴ x2+y2−

x

2

= 0 ⇒ (x2−

x

2

)+y2 = 0
⇒ (x2−

x

2

+(

1

4

)2)+y2 = 0+(

1

4

)2 ⇒ (x−

1

4

)2+y2 = (

1

4

)2
Comparing it with (x–h)2+(y–k)2 = r2, we have h =

1

4

, k = 0 and r =

1

4

Thus co-ordinates of the centre are (

1

4

,0) and radius is

1

4

.