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NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 13
Total: 72
lim
x→0
sinax
bx
Solution:  
We have,
lim
x→0
sinax
bx
 =
lim
x→0
sinax
ax
.
ax
bx
=
lim
x→0
sinax
ax
.
a
b
 =
a
b
(
lim
x→0
sinax
ax
) =
a
b
Since
lim
θ→0
sinθ
0
 = 1
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