Test Index

NCERT Class XI Mathematics - Limits and Derivatives - Solutions

© examsnet.com
Question : 13 of 72
Marks: +1, -0
lim
x→0
sinax
bx
Solution:  
We have,
lim
x→0
sinax
bx
 =
lim
x→0
sinax
ax
.
ax
bx
=
lim
x→0
sinax
ax
.
a
b
 =
a
b
(
lim
x→0
sinax
ax
) =
a
b
Since
lim
θ→0
sinθ
0
 = 1
© examsnet.com
Go to Question:
Prev Question
Next Question