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NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 14
Total: 72
lim
x→0
sinax
sinbx
 , a , b ≠ 0
Solution:  
We have,
lim
x→0
sinax
sinbx
 , a , b ≠ 0
=
lim
x→0
sinax
ax
.
bx
sinbx
.
ax
bx
 =
lim
x→0
sinax
ax
 .
lim
x→0
1
(
sinbx
bx
)
.
a
b
=
a
b
 . (1) . (1) =
a
b
.
Since
lim
θ→0
sinθ
θ
 = 1.
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