Test Index

NCERT Class XI Mathematics - Limits and Derivatives - Solutions

© examsnet.com
Question : 6
Total: 72
lim
x→0
(x+1)5−1
x
Solution:  
We have,
lim
x→0
(x+1)5−1
x
 (0/0 form)
Put y = 1 + x, so that y → 1 as x → 0
Then
lim
x→0
(x+1)5−1
x
 =
lim
y→1
y5−1
y−1
 = 5(1)5−1 = 5.
[Using
lim
x→a
xn−an
x−a
 = n(a)n−1]
© examsnet.com
Go to Question:
Prev Question
Next Question