NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 7
Total: 72
lim
x2
3x2x10
x24
Solution:  
We have,
lim
x2
3x2x10
x24
(0/0 form) =
lim
x2
[3x26x+5x10]
(x2)(x+2)

=
lim
x2
[3x(x2)+5(x2)]
(x2)(x+2)
=
lim
x2
(3x+5)(x2)
(x2)(x+2)
=
lim
x2
3x+5
x+2

=
3(2)+5
2+2
=
6+5
4
=
11
4
.
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