The inequality is

1

2

(

3x

5

+4) ≥

1

3

(x−6) or ,

1

2

(

3x+20

5

) ≥

1

3

(x−6)
Multiplying both sides by 30,
3(3x + 20) ≥ 10(x – 6) or, 9x + 60 ≥ 10x – 60
Transposing 10x to L.H.S. and 60 to R.H.S., we get
∴ 9x – 10x ≥ – 60 – 60 or –x ≥ –120
Multiplying both sides by –1, we get x ≤ 120
∴ The solution is (–∞, 120].