NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 52
Total: 106
Find the sum to n terms of the sequence, 8, 88, 888, 8888 ...... .
Solution:  
This is not a G.P., however we can relate it to a G.P. by writing the terms as Sn = 8 +88 + 888 + 8888 + ...... to n terms
Now, Sn =
8
9
[9 + 99 + 999 ...... to n terms]
=
8
9
[(10 - 1) + (100 - 1) + (1000 - 1) + ... to n terms]
=
8
9
[(10 + 100 + 1000 + ... to n terms) - (1 + 1 + ... to n temrs)]
=
8
9
[(10 + 102+103 + ... to n terms) - (1 + 1 + 1 + ... to n terms)]
=
8
9
[
10(10n1)
9
n
]

Since Sn = a
(rn1)
r1
, if |r| > 1.
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