NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 99
Total: 106
Find the sum of the following series up to n terms :
(i) 5 + 55 + 555 + .....
(ii) .6 + .66 + .666 + .....
Solution:  
(i) Let Sn = 5 + 55 + 555 + ..... to n terms, which can be written as
Sn =
5
9
[9 + 99 + 999 + ... to n terms]
=
5
9
[(10 - 1) + (100 - 1) + (1000 - 1) + ... to n terms]
=
5
9
[(10 + 100 + 1000 + ... to n terms) - (1 + 1 + ... to n terms)]
=
5
9
[
10(10n1)
101
n
]
=
5
9
[
10
9
(10n1)
n
]
=
50
81
(10n1)
5n
9

(ii) Let Sn = 0.6 + 0.66 + 0.666 + ...... to n terms, which can be written as
Sn =
6
9
[0.9 + 0.99 + 0.999 + ... to n terms]
=
6
9
[(1 - 0.1) + (1 - 0.01) + (1 - 0.001) + ... to n terms]
=
6
9
[(1 + 1 + ... to n terms) - (0.1 + 0.01 + 0.001 + ... to n terms)]
=
2
3
[n0.1
(1(0.1)n)
10.1
]
=
2
3
[n
1
9
(1
1
10n
)
]
=
2n
3
2
27
(1
1
10n
)
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