NCERT Class XI Mathematics - Statistics - Solutions

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Question : 18
Total: 34
Find the mean and standard deviation using short-cut method.
xi 60 61 62 63 64 65 66 67 68
fi 2 1 12 29 25 12 10 4 5

Solution:  
xi fi ui = xi64 fiui fiui2
60 2 -4 - 832
611 -3 - 3 9
6212- 2 - 2448
6329 - 1 -29 29
64 25 0 0 0
65 12 112 12
66 10 2 20 40
674 3 12 36
685 4 20 80
100 0 286

Let assumed mean (A) = 64; Mean (
x
)
= A +
Σfiui
N
= 64 +
0
100
= 64
S.D. (σ) =
1
N
NΣfiui2(Σfiui)2
=
1
100
100×286(0)2

=
1
100
28600
=
1
100
× 169.1 = 1.69
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