NCERT Class XI Mathematics - Statistics - Solutions

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Question : 8
Total: 34
xi 15 21 27 30 35
fi 3 5 6 7 8

Solution:  
xi fi c.f. |xi7| fi|xi7|
15 3 3 15 45
21 5 8 9 18
27 6 14 3 18
30 7 21 0 0
35 8 29 5 40
29 148

Here,
N
2
=
29
2
= 14.5
The c.f. just greater than 14.5 is 21 and the corresponding value of x is 30.
So, Median (M) = 30
∴ M.D. about median =
1
N
n
Σ
i=1
fi
|xiM
|
=
1
29
× 148 = 5.1
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