NCERT Class XI Mathematics - Straight Lines - Solutions
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Question : 42
Total: 74
Find equation of the line perpendicular to the line x – 7y + 5 = 0 and having x intercept 3.
Solution:
Given equation is x – 7y + 5 = 0 ... (i)
Slope of this line =
∴ Slope of any line perpendicular to the line (i) is –7 and passes through
(3, 0) then y – 0 = –7(x – 3)
[Q Product of slope of perpendicular lines is –1]
⇒ y = –7x + 21 ⇒ 7x + y – 21 = 0, is the required equation of line
Slope of this line =
∴ Slope of any line perpendicular to the line (i) is –7 and passes through
(3, 0) then y – 0 = –7(x – 3)
[Q Product of slope of perpendicular lines is –1]
⇒ y = –7x + 21 ⇒ 7x + y – 21 = 0, is the required equation of line
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