The given equation of lines are
4x + 7y – 3 = 0 ... (i)
and 2x – 3y + 1 = 0 ... (ii)
On solving (i) and (ii), we get x =

1

13

, y =

5

13

Thus the lines (i) and (ii) meets at (

1

13

,

5

13

)
Hence the equation of the line passing through (

1

13

,

5

13

) and has equal intercepts on the axes is

1

13a

+

5

13a

= 1 [Since a = b]
⇒

6

13a

= 1 ⇒ 6 = 13a ⇒ a =

6

13

.
∴ The required equation of line is 13(x + y) = 6.