NCERT Class XI Mathematics - Trigonometric Functions - Solutions
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Question : 29
Total: 61
Solution:
We have , L.H.S. = s i n 2 s i n 2
= sin (6x - 4x) sin (6x + 4x) [Sinces i n 2 s i n 2
= sin 2x sin 10x = R.H.S.
= sin (6x - 4x) sin (6x + 4x) [Since
= sin 2x sin 10x = R.H.S.
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