NCERT Class XI Mathematics - Trigonometric Functions - Solutions
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Question : 30
Total: 61
Solution:
We have, L.H.S.= c o s 2 c o s 2
= sin(2x + 6x) sin(6x – 2x)
[Sincec o s 2 A − c o s 2 B
= sin(8x) sin(4x) = R.H.S.
= sin(2x + 6x) sin(6x – 2x)
[Since
= sin(8x) sin(4x) = R.H.S.
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