Laws of Motion

Question : 6

Total: 40

A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 m s‌–1 to 3.5 m s‌–1 in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

Solution:

Here, m=3.0 kg,u=2.0 m s−1;
v=3.5 m s−1,t=25 s
Now, v=u+at
3.5=2+a×25
⇒a=

3.5−2

=0.06 ms−2
Therefore, force acting on the body,
F=ma=3×0.06=0.18N in the direction of motion.

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