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Laws of Motion

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Question : 7
Total: 40
A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.
Solution:  
Here, m=5kg,
→
a
=?
→
F
1=OA=8N;
→
F
2=OB=6N
Resultant force,
→
F
=OC
=√F12+F22 =√82+62=10N
Therefore magnitude of the acceleration produced
a=
F
m
=
10
5
=2ms−2
This is the direction of resultant force and hence the direction of acceleration of the body.
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