Mechanical Properties of Solids

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Question : 10
Total: 21
A rigid bar of mass 15 kg is supported symmetrically by three wires each 2.0 m long. These at each end are of copper and the middle one is of iron. Determine the ratio of their diameters if each is to have the same tension.
[Young’s modulus of elasticity for copper and steel are 110×109Nm2 and 190×109Nm2 respectively.]
Solution:  
As each wire has same tension F, so each wire has same extension due to mass of rigid bar. As each wire is of same length, hence each wire has same strain. If D is the diameter of wire, then
Y=
4FπD2
strain
or D2
1
Y

DCu
D iron
=
Y iron
YCu

=
190×109
110×109

=
19
11
=1.31
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