Mechanical Properties of Solids
© examsnet.com
Question : 9
Total: 21
A steel cable with a radius of 1.5 cm supports a chairlift at a ski area. If the maximum stress is not to exceed 10 8 N m – 2
Solution:
Here, maximum stress = 10 8 N m – 2
radius of the cable, r = 1.5 cm = 0.015 m.
Therefore, area of cross-section of the cable,
A = π r 2 = π × ( 0.0152 ) 2
= 2.25 × 10 − 4 π m 2
The maximum load, the cable can support,
F = maximum stress × area of cross-section
= 10 8 × 2.25 × 10 − 4 π
= 7.07 × 10 4 N
radius of the cable, r = 1.5 cm = 0.015 m.
Therefore, area of cross-section of the cable,
The maximum load, the cable can support,
F = maximum stress × area of cross-section
© examsnet.com
Go to Question: