Mechanical Properties of Solids

Question : 8

Total: 21

A piece of copper having a rectangular cross-section of 15.2 mm × 19.1 mm is pulled in tension with 44, 500 N, force producing only elastic deformation. Calculate the resulting strain. Shear modulus of elasticity of copper is 42×109Nm–2.

Solution:

Here, A=15.2×19.2×10−6 m2;
F=44,500N;η=42×109N m−2
Strain =

stress

modulus of elasticity

F∕A

44500

15.2×19.2×10−6×42×109

=3.65×10−3

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