Oscillations
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Question : 14
Total: 25
The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of 200 rad min – 1
Solution:
Stroke of piston = 2 times the amplitude. Let A = amplitude, Stroke = 1 m (given)
∴ 1 = 2 A A =
m
Now , v max = ω A = 200 ×
= 100 m ∕ min =
m s − 1
=
m s − 1 = 1.67 m s − 1
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