Oscillations

Question : 15

Total: 25

The acceleration due to gravity on the surface of moon is 1.7ms–2. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s? (g on the surface of earth is 9.8 ms–2)

Solution:

Using the formula T=2π√

, we get
For earth Te=2π√

,...(i)
and for moon, Tm=2π√

...(ii)
Dividing (ii) by (i), we get

=√

9.8

1.7

or Tm=3.5×√

=3.5√5.7647
=3.5×2.4 or Tm=8.4s

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