Systems of Particles and Rotational Motion

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Question : 11
Total: 33
Torques of equal magnitude are applied to a hollow cylinder and a solid sphere, both having the same mass and radius. The cylinder is free to rotate about its standard axis of symmetry, and the sphere is free to rotate about an axis passing through its centre. Which of the two will acquire a greater angular speed after a given time.
Solution:  
Let M and R be mass and radius of the hollow cylinder and the solid sphere, then,
Moment of inertia of the hollow cylinder about its axis of symmetry,
I1=MR2
Moment of inertia of the solid sphere about its axis through its centre
I2=
2
5
M
R2

Torque τ=Iα
where α is angular acceleration.
I1α1=I2α2
α2
α1
=
I1
I2
=
MR2
2
5
M
R2
=
5
2

α2=2.5α1 or α2>α1
from ω=ω0+αt, we find that for given ω0 and t,ω2>ω1, angular speed of solid sphere will be greater than the angular speed of hollow cylinder.
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