Systems of Particles and Rotational Motion
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Question : 12
Total: 33
A solid cylinder of mass 20 kg rotates about its axis with angular speed 100 rad s– 1
Solution:
Mass of solid cylinder = 20 kg
Radius of solid cylinder = 0.25 m
Angular velocity w = 100 rad s– 1
Therefore, MI of the cylinder about its axis
I =
M R 2 =
× 20 × ( 0.25 ) 2 = 0.625 k g m 2
K.E. of the rotating cylinder
=
I ω 2 =
× ( 0.625 ) × ( 100 ) 2 = 3125 J
Angular momentumL = I ω = 0.625 × 100 = 62.5 k g m 2 s − 1
Radius of solid cylinder = 0.25 m
Angular velocity w = 100 rad s
Therefore, MI of the cylinder about its axis
K.E. of the rotating cylinder
Angular momentum
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