Systems of Particles and Rotational Motion

Question : 17

Total: 33

A metre sticks is balanced on a knife edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12.0 cm mark, the stick is found to be balanced at 45.0 cm. What is the mass of the metre stick?

Solution:

Let m be the mass of metre stick concentrated at C, the 50 cm mark as shown in figure.

Take moment of inertia about C′, at the 45 cm mark we get,10g(45–12)=mg(50–45)
⇒10g×33=mg×5
m=

10×33

=66‌gram

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