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NCERT Class XII Chapter
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Question : 3
Total: 18
What is the shortest wavelength present in the Paschen series of spectral lines?
Solution:  
For shortest wavelength of Paschen series, n1 = 3, n2 = ∞
∴
1
λS
 = R [
1
32
−
1
∞
] =
R
9
 or λs =
9
R
 =
9
1.097×107
= 8.2041 × 10–7 m = 8204.1 Å.
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