Test Index

NCERT Class XII Chapter
Atoms
Questions With Solutions

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Question : 4
Total: 18
A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom makes a transition from the upper level to the lower level?
Solution:  
Here E = 2.3 eV = 2.3 × 1.6 × 10–19 J
As E = hυ
∴ Frequency , υ =
E
h
 =
2.3×1.6×10−19
6.6×10−34
 = 5.6 × 1014 Hz
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