Test Index

NCERT Class XII Chapter
Nuclei
Questions With Solutions

© examsnet.com
Question : 16
Total: 31
Suppose, we think of fission of a
56
‌
26
Fe nucleus into two equal fragments,
28
‌
13
Al. Is the fission energetically possible? Argue by working out Q of the process.
Given , m (
56
‌
26
Fe) = 55.93494u and m (
28
‌
13
Al) = 27.98191u.
Solution:  
The fission of Fe-56 into two fragments of
28
‌
13
Al with energy released Q can be written as
56
‌
26
Fe →
28
‌
13
Al +
28
‌
13
Al + Q
Q = [m(
56
‌
26
Fe)−2m(
28
‌
13
Al)]c2 = [55.93494 – 2 × 27.98191] × 931.5 MeV
= – 0.02888 × 931.5 = – 26.90 MeV
As the Q-value is negative, the fission is not possible energetically.
© examsnet.com
Go to Question:
Prev Question
Next Question