NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions
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Question : 26
Total: 39
The decomposition of a hydrocarbon follows the equation
k = ( 4.5 × 10 11 s − 1 ) e − 28000 k ∕ T E a .
Solution:
Arrhenius equation, k = A e − E d ∕ R T
Given equation isk = ( 4.5 × 10 11 s − 1 ) e − 2800 K ∕ T
Comparing both the equations, we get
= −
or,E a = 28000 K × R
= 28000 × 8.314
= 232.79 k J m o l − 1
Given equation is
Comparing both the equations, we get
or,
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