NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions

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Question : 28
Total: 39
The decomposition of A into product has value of k as 4.5 × 103s1 at 10°C and energy of activation 60 kJ mol. At what temperature would k be 1.5 × 104s1 ?
Solution:  
Given k1=4.5×103s1
T1=10+273K
=283 K;
k2=1.5×104 s1,
T2=?,Ea=60 kJ mol1
Applying Arrhenius equation,
log
k2
k1
=
Ea
2.303R
(
T2T1
T1T2
)

log
1.5×104
4.5×103
=
60000
2.303×8.314
(
T2283
283T2
)

or, log3.333=3133.63 (
T2283
283T2
)

or,
0.5228
3133.63
=
T2283
283T2

or, 0.0472T2=T2283 or 0.9528T2=283
or, T2=
283
0.9528
=297 K
=297273=240C
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