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NCERT Class XII Chemistry
Chapter - Solutions
Questions with Solutions

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Question : 8
Total: 53
An antifreeze solution is prepared from 222.6 g of ethylene glycol,C2H4(OH)2 and 200 g of water. Calculate the molality of the solution. If the density of the solution is 1.072 g mL‌–1, then what shall be the molarity of the solution?
Solution:  
Mass of the solute, C2H4(OH)2=222.6g
Molar mass of solute, C2H4( ‌OH)2=62 g mol−1
∴‌ Moles of the solute =
222.6 g
62 g mol−1
=3.59
Mass of the solvent =200‌g=0.200‌kg
Volume of solution =
422.6
1.072 g mL−1
=394.2 ‌mL=0.3942L
Molality =
Number‌of‌moles‌of‌solute
Mass‌of‌solvent‌in ‌kg
 =
3.59
0.2
=17.95m
Molarity =
3.59‌moles
0.3942 L
 =9.11 ‌mol‌L−1
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