NCERT Class XII Chemistry
Chapter - The d- and f-Block Elements
Questions with Solutions

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Question : 16
Total: 49
Describe the preparation of potassium permanganate. How does the acidified permanganate solution react with (i) iron (ii) ions (ii) SO2 and (iii) oxalic acid ? Write the ionic equations for the reactions.
Solution:  
Potassium permanganate (KMnO4) is prepared by the fusion of a mixture of pyrolusite (MnO2) , potassium hydroxide and oxygen, first green coloured potassium manganate is formed.
2MnO2+4KOH+O2→2K2MnO4+2H2O
The potassium manganate is extracted bywater, which then undergoes disproportionation in neutral or acidic solution to give potassium permanganate.
Electrolytically :
3MnO42–+4H+→2MnO4–+MnO2+2H2O
In acidic medium of dilute sulphuric acid, KMnO4 acts as strong oxidising agent andit reacts as:
MnO4–+8H++5e–→Mn2++4H2O
(i) Iron(II) solution : Ferrous (Fe2+) ion solution to ferric (Fe3+) ion solution.
MnO4–+8H++5e–→Mn2++4H2O
‌‌‌‌‌‌‌‌‌‌‌‌‌‌‌‌‌‌‌‌5Fe2+→5Fe3++5e–
––––––––––––––––––––––––––––––––––––––––––––
MnO4–+5Fe2++8H+→Mn2++5Fe3++4H2O
––––––––––––––––––––––––––––––––––––––––––––––
(ii) Sulphur dioxide (SO2)
MnO4–+8H++5e–→Mn2++4H2O]×2
10H2O+5SO2→5SO42–+20H++10e–
––––––––––––––––––––––––––––––––––––––––––––––
2MnO4–+5SO2+2H2O→5SO42–+2Mn2++4H+
––––––––––––––––––––––––––––––––––––––––––––––

(iii)Oxalic acid
MnO4–+8H++5e–→Mn2++4H2O]×2
10H2O+5SO2→5SO42–+20H++10e–
––––––––––––––––––––––––––––––––––––––––––––––
2MnO4–+5SO2+2H2O→5SO42–+2Mn2++4H+
––––––––––––––––––––––––––––––––––––––––––––––
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