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AIEEE 2002 Math Solved Paper
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© examsnet.com
Question : 9
Total: 74
Difference between the corresponding roots of
x
2
+
a
x
+
b
=
0
and
x
2
+
b
x
+
a
=
0
is same and
a
≠
b
, then
a
+
b
+
4
=
0
a
+
b
−
4
=
0
a
−
b
−
4
=
0
a
−
b
+
4
=
0
Validate
Solution:
Let
α
,
β
and
γ
,
δ
be the roots of the equations
x
2
+
a
x
+
b
=
0
and
x
2
+
b
x
+
a
=
0
respectively.
∴
α
+
β
=
−
a
,
α
β
=
b
and
γ
+
δ
=
−
b
,
γ
δ
=
a
Given
|
α
−
β
|
=
|
γ
−
δ
|
⇒
(
α
−
β
)
2
=
(
γ
−
δ
)
2
⇒
(
α
+
β
)
2
−
4
α
β
=
(
γ
+
δ
)
2
−
4
γ
δ
⇒
a
2
−
4
b
=
b
2
−
4
a
⇒
(
a
2
−
b
2
)
+
4
(
a
−
b
)
=
0
⇒
a
+
b
+
4
=
0
(
as
a
≠
b
)
© examsnet.com
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