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AIEEE 2002 Physics Solved Paper
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© examsnet.com
Question : 32
Total: 75
Two spheres of the same material have radii
1
m
and
4
m
and temperatures
4000
K
and
2000
K
respectively. The ratio of the energy radiated per second by the first sphere to that by the second is
1
:
1
16
:
1
4
:
1
1
:
9
Validate
Solution:
The energy radiated per second is given by
E
=
e
σ
T
4
A
For same material
e
is same.
σ
is stefan's constant
∴
E
1
E
2
=
T
1
4
A
1
T
2
4
A
2
=
T
1
4
4
π
r
1
2
T
2
4
4
π
r
2
2
=
(
4000
)
4
×
1
2
(
2000
)
4
×
4
2
=
1
1
© examsnet.com
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