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AIEEE 2002 Physics Solved Paper
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© examsnet.com
Question : 58
Total: 75
In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280 . current in primary coil is
4
A
, then that in the secondary coil is
4A
2A
6A
10A
Validate
Solution:
N
p
=
140
,
N
s
=
280
,
I
p
=
4
A
,
I
s
=
?
For a transformer
I
s
I
p
=
N
p
N
s
⇒
I
s
4
=
140
280
⇒
I
s
=
2
A
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