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AIEEE 2003 Chemistry Solved Paper
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© examsnet.com
Question : 4
Total: 76
The orbital angular momentum for an electron revolving in an orbit is given by
√
l
(
l
+
1
)
h
2
π
. This momentum for an s-electron will be given by
zero
h
2
π
√
2
h
2
π
+
1
2
h
2
π
Validate
Solution:
For s-electron
I
=
0
∴
√
l
(
l
+
1
)
h
2
π
=
√
0
(
0
+
1
)
h
2
π
=
√
0
h
2
π
=
0
(zero)
© examsnet.com
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