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AIEEE 2003 Physics Solved Paper
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© examsnet.com
Question : 34
Total: 74
A metal wire of linear mass density of
9.8
g
/
m
is stretched with a tension of
10
kg
−
w
t
between two rigid supports 1 metre apart. The wire passes at its middle point between the poles of a permanent magnet, and it vibrates in resonance when carrying an alternating current of frequency
n
. The frequency
n
of the alternating source is
50 Hz
100 Hz
200 Hz
25 Hz
Validate
Solution:
KEY CONCEPT : For a string vibrating between two rigid support, the fundamental frequency is given by
n
=
1
2
ℓ
√
T
µ
=
1
2
×
√
10
×
9.8
9.8
×
10
−
3
=
50
H
z
As the string is vibrating in resonance to a.c of frequency
n
, therefore both the frequencies are same.
© examsnet.com
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